Lean Six Sigma Green Belt Sample Paper 2: Measure This sample paper will check your knowledge on Measure phase for LSS Green Belt Click on 'Next' to start 1. The design specification for a cap diameter is 2 ± 0.05 cm. The diameter data follows normal distribution with mean of 2.02 cm and standard deviation of 0.01 cm. Calculate Cp, Cpk and give appropriate recommendationCp=1.67, Cpk=1; Process mean to be shifted to targetCp=0.33, Cpk=0.2; Process mean to be shifted to targetCp=0.33, Cpk=0.33; Variation to be reducedCp=1.67, Cpk=1; Variation to be reduced2. The purpose of operational definition isto provide a single, agreed upon meaning of the CTQ to all the stakeholdersto ensure reliability and consistency of measurementto provide a clear and understandable description of what is to be observed and measuredAll the above3. 100 transactions were inspected, 20 errors were found in 15 transactions. What is DPU?0.0221.330.24. Which of the following statements is FALSE?Sigma level can be calculated for both discrete and continuous dataIf standard deviation decreases, Sigma level increasesSigma level can be converted to a corresponding DPMOAll processes should operate at a six sigma level5. Quality team at an online retailer checks images and classifies them as “OK” or “NOT OK”. Although 70% of the images are handled by automation, 30% images are still checked manually which the system fails to classify correctly. Which of the following is an appropriate method to validate the manual measurement system?Focus on the operational definitionLogical validationGage Repeatability and ReproducibilityAttribute Agreement Analysis6. All the statements given below are false, EXCEPTCpk is always equal to or greater than CpIf the Cpk value becomes zero, then the process average is at one of the specification limitsThe Cp and Cpk values will be 2 if the process is perfectly centeredIn both Cp and Cpk, the lower the value, higher the performance level7. During frisking at airports, the metal detectors are passed over the metal belt first. This is an example of:Logical validationRepeatabilityAttribute agreement analysisGage R & R8. An appraiser provides consistent scores every time he makes a measurement. All other appraisers show similar performance. However many of them do not agree with the standard answer. The issue is with the:Appraiser RepeatabilityAppraiser AccuracyAppraiser ReproducibilityTeam repeatability9. As per the SLA, all complaints should be resolved within 8 hours. Currently the average resolution time is 4.57 hours and standard deviation is 0.8 hours. What is DPMO?4.299.05.97None of the above10. DPMO can be calculated from:Continuous data following normal distribution, provided specifications are knownDefects data provided OFE is knownDefective dataAll the above11. The FTY’s of four sequential process steps are 0.8, 0.91, 0.90, 0.99. What is the RTY and Zst respectively?RTY = 0.6486; Zst = 0.38RTY = 0.99; Zst = 3.83RTY = 0.6486; Zst = 1.88RTY = 0.7920; Zst = 2.3112. Which of the following process has the highest Capability Index (Cp)?Process A - USL = 30, LSL = 20, Mean = 20, Standard Deviation = 1Process B - USL = 30, LSL = 20, Mean = 15, Standard Deviation = 2Process C - USL = 31, LSL = 21, Mean = 25, Standard Deviation = 1Process AProcess BProcess CBoth Process A and C13. “Higher the better” applies to all the following, EXCEPTSigma levelCpDPUYieldTime is Up!