April 5, 201313 yr How did people arrive that only 3.14 defects are allowed for million opportunities for six sigma? Is there any mathematical/statistical proof for this? Likewise for 3sigma,4sigma and 5sigma?
August 29, 201312 yr This can be understood with the help of Normal Distribution. Consider the Upper Specification Limit (USL) as Mean + n * S.D. Consider the Lower Specification Limit (USL) as Mean - n * S.D. The area between the USL & LSL is the defect free area and the outliers are the defects. In case of Six Sigma, n = 6. The area under the curve is 0.9999966.Outside the curve, we are left with .0000034, this means 3.4 defects per million.
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